Remove Decimal Places

I have problem to remove Decimal Places. I have formula and Summary field which sums integer numbers, but they appear in this format 9.00. If I use Crystal Report Designer I can fix this by using Format Field->Number but I want to do this programmatically.This worked for me when I had a number that I wanted to display without the decimals:

ToText({qry_LeaseExtensionDataByQtr_2.Exp Qtr},0)|||Thank you!

I know that this work, but I'm wondering why I can set Field Format thru the Report Designer and can't set it programmatically.|||That solution worked perfect for my situation. I had a GenderID that needed to be concatenated with names, address etc.. My results were 1.00LisaSmithWestAve. The 1.00 was unacceptable. I created @.toTextGender that did this: totext(genderID,0). I then used that formula in my formula that concatenates my data. Thanks for the info.

Remove alpha chars & all spaces in field [UPDATED]

Hello,

I need to strip out all alpha chars and spaces in a given field and return only the numbers.

I've tried =CInt(Fields!Info.Value) and get an unexplained error. If the data was formatted consitantly I could simply do a RTrim or Right, but the number strings are not the same, some have spaces as in phone numbers (1 800 555 1212) or don't have a leading 1. Most instances are correct for my purpose (8005551212).

Any help would be appreciated.

UPDATE: Using the Replace function =Replace(Fields!Info.Value, " ","") gets me almost there. Now I should be able to use a Right, 10 function to return my desired value. Is it possible to combine these two funtions together?

Hi,

If it is possible to call the SQLServer function Please write the following function:

create FUNCTION [dbo].[GetNumberFromData]

(@.data VARCHAR(MAX))

RETURNS VARCHAR(MAX)

AS

BEGIN

DECLARE @.pos BIGINT,@.char CHAR(1),@.rightside VARCHAR(MAX)

/*Set @.data = rtrim(ltrim(@.data))

While CharIndex(' ',@.data)>0

Select @.data = Replace(@.data, ' ', '')*/

SET @.pos = 1

WHILE (@.data like '%[^0-9]%') AND @.pos <= LEN(@.data)

BEGIN

SET @.char = SUBSTRING(@.data, @.pos, 1)

IF @.char like '%[0-9]%'SET @.pos = @.pos + 1

ELSE

BEGIN

SELECT @.rightside = SUBSTRING(@.data, @.pos + 1, LEN(@.data)),@.data = CASE WHEN @.rightside like '%[0-9]%' THEN

LEFT(@.data, @.pos - 1) + @.rightside

ELSE

LEFT(@.data, @.pos - 1)END

END

END

IF @.data like '%[^0-9]%' OR LEN(@.data) = 0

SET @.data = NULL

RETURN LTRIM(RTRIM(@.data))

End

and call the function like this:

If you can't able to call the function from report put the below statement in the stored procedure.and call that SP in your report.

select [dbo].[GetNumberFromData](' 1 800 , dd 798 hjjhjj kal 8976 asdf ')

Hope this helps.

Thanks

|||

Hello,

Here's a custom function I wrote that will strip all the non-numeric characters from a string. Go to Report Properties from the report menu, then in the Code tab, enter this:

Public Function GetNumbers(s as string) as Integer

Dim str as String

Dim i as Integer

str = ""

i = 0

While i < Len(s)

If (Asc(Mid(s, i + 1, 1)) >= 48 and Asc(Mid(s, i + 1, 1)) <= 57)

str = str + Mid(s, i + 1, 1)

End If

i = i + 1

End While

return cInt(str)

End Function

Then, in your textbox for the numbers, use this as your expression:

=Code.GetNumbers(Fields@.!Info.Value)

As for your Update... yes, you can use them both at the same time. =Right(Replace(Fields!Info.Value, " ", ""), 10)

Hope this helps.

Jarret

|||Thanks a BUNCH!

Remove all non digit characters from some string

Hello.
How can I write some stored procedure or function to which I will pass the
string and it will return me only numbers from my string?
Exactly I need to remove all non digit characters from some string.
Tank you.
You could write an extended stored proc in a dll...dont know if this best
solution though
"David Dvali" <david_dvali@.hotmail.com> wrote in message
news:%23iSW2D$0FHA.2348@.TK2MSFTNGP15.phx.gbl...
> Hello.
> How can I write some stored procedure or function to which I will pass the
> string and it will return me only numbers from my string?
> Exactly I need to remove all non digit characters from some string.
> Tank you.
>
|||David,
If you have a fixed set of characters to remove i.e., like with a phone
number you could do something like this:
DECLARE @.TELEPHONENUMBER VARCHAR(25)
SET @.TELEPHONENUMBER = '(503)999-1851'
SELECT REPLACE(REPLACE(REPLACE(REPLACE(@.TELEPHONENUMBER,' (',''),')',''),'
',''),'-','')
HTH
Jerry
"David Dvali" <david_dvali@.hotmail.com> wrote in message
news:%23iSW2D$0FHA.2348@.TK2MSFTNGP15.phx.gbl...
> Hello.
> How can I write some stored procedure or function to which I will pass the
> string and it will return me only numbers from my string?
> Exactly I need to remove all non digit characters from some string.
> Tank you.
>
|||Hi,
This might not be the most efficient way of doing it but it works :-)
DECLARE @.InputString varchar(32)
DECLARE @.OutputString varchar(32)
DECLARE @.i int
SET @.InputString =3D 'ABC123!=A3$456'
SET @.i =3D NULLIF(PATINDEX('%[0-9]%',@.InputString),0)
WHILE @.i IS NOT NULL
BEGIN
SET @.OutputString =3D isnull(@.OutputString,'') +
SUBSTRING(@.Inputstring, @.i, 1)
SET @.i =3D @.i +
NULLIF(PATINDEX('%[0-9]%',SUBSTRING(@.InputString,@.i+1,len(@.InputString))) ,0)
END
SELECT @.OutputString -- This gives '123456'
I would normally use a auxilary numbers table instead of the loop, but
didn't have time to go through that in this example.
Jerry Spivey wrote:[vbcol=seagreen]
> David,
> If you have a fixed set of characters to remove i.e., like with a phone
> number you could do something like this:
> DECLARE @.TELEPHONENUMBER VARCHAR(25)
> SET @.TELEPHONENUMBER =3D '(503)999-1851'
> SELECT REPLACE(REPLACE(REPLACE(REPLACE(@.TELEPHONENUMBER,' (',''),')',''),'
> ',''),'-','')
> HTH
> Jerry
> "David Dvali" <david_dvali@.hotmail.com> wrote in message
> news:%23iSW2D$0FHA.2348@.TK2MSFTNGP15.phx.gbl...
the[vbcol=seagreen]
|||This should do the trick...
DECLARE @.Index smallint
DECLARE @.SearchString varchar(25)
DECLARE @.StringLength smallint
DECLARE @.CurrentChar Char(1)
SET @.searchstring = 'ab35d0l2rle.p1C9,:$#47)('
SET @.StringLength = LEN(@.SearchString)
SET @.Index = 1
WHILE @.Index <= @.StringLength
BEGIN
SET @.CurrentChar = SUBSTRING(@.SearchString, @.index, 1)
if @.CurrentChar NOT IN ('0', '1', '2', '3', '4', '5', '6', '7', '8', '9')
BEGIN
SET @.SearchString = REPLACE(@.SearchString, @.CurrentChar, 'X')
END
SET @.Index = @.Index + 1
END
SELECT REPLACE(@.SearchString, 'X','')
Returns 35021947
Replace all the non-numeric values with 'X' (so as to not screw up the WHILE
index,) then replace all Xs with an empty string. In a stored proc,
@.SearchString would be the parameter...
HTH,
Mike

Remove all non digit characters from some string

Hello.
How can I write some stored procedure or function to which I will pass the
string and it will return me only numbers from my string?
Exactly I need to remove all non digit characters from some string.
Tank you.You could write an extended stored proc in a dll...dont know if this best
solution though
"David Dvali" <david_dvali@.hotmail.com> wrote in message
news:%23iSW2D$0FHA.2348@.TK2MSFTNGP15.phx.gbl...
> Hello.
> How can I write some stored procedure or function to which I will pass the
> string and it will return me only numbers from my string?
> Exactly I need to remove all non digit characters from some string.
> Tank you.
>|||David,
If you have a fixed set of characters to remove i.e., like with a phone
number you could do something like this:
DECLARE @.TELEPHONENUMBER VARCHAR(25)
SET @.TELEPHONENUMBER = '(503)999-1851'
SELECT REPLACE(REPLACE(REPLACE(REPLACE(@.TELEPHONENUMBER,'(',''),')',''),'
',''),'-','')
HTH
Jerry
"David Dvali" <david_dvali@.hotmail.com> wrote in message
news:%23iSW2D$0FHA.2348@.TK2MSFTNGP15.phx.gbl...
> Hello.
> How can I write some stored procedure or function to which I will pass the
> string and it will return me only numbers from my string?
> Exactly I need to remove all non digit characters from some string.
> Tank you.
>|||Hi,
This might not be the most efficient way of doing it but it works :-)
DECLARE @.InputString varchar(32)
DECLARE @.OutputString varchar(32)
DECLARE @.i int
SET @.InputString =3D 'ABC123!=A3$456'
SET @.i =3D NULLIF(PATINDEX('%[0-9]%',@.InputString),0)
WHILE @.i IS NOT NULL
BEGIN
SET @.OutputString =3D isnull(@.OutputString,'') +
SUBSTRING(@.Inputstring, @.i, 1)
SET @.i =3D @.i +
NULLIF(PATINDEX('%[0-9]%',SUBSTRING(@.InputString,@.i+1,len(@.InputString))),0)
END
SELECT @.OutputString -- This gives '123456'
I would normally use a auxilary numbers table instead of the loop, but
didn't have time to go through that in this example.
Jerry Spivey wrote:
> David,
> If you have a fixed set of characters to remove i.e., like with a phone
> number you could do something like this:
> DECLARE @.TELEPHONENUMBER VARCHAR(25)
> SET @.TELEPHONENUMBER =3D '(503)999-1851'
> SELECT REPLACE(REPLACE(REPLACE(REPLACE(@.TELEPHONENUMBER,'(',''),')',''),'
> ',''),'-','')
> HTH
> Jerry
> "David Dvali" <david_dvali@.hotmail.com> wrote in message
> news:%23iSW2D$0FHA.2348@.TK2MSFTNGP15.phx.gbl...
> > Hello.
> >
> > How can I write some stored procedure or function to which I will pass =the
> > string and it will return me only numbers from my string?
> > Exactly I need to remove all non digit characters from some string.
> >
> > Tank you.
> >|||This should do the trick...
DECLARE @.Index smallint
DECLARE @.SearchString varchar(25)
DECLARE @.StringLength smallint
DECLARE @.CurrentChar Char(1)
SET @.searchstring = 'ab35d0l2rle.p1C9,:$#47)('
SET @.StringLength = LEN(@.SearchString)
SET @.Index = 1
WHILE @.Index <= @.StringLength
BEGIN
SET @.CurrentChar = SUBSTRING(@.SearchString, @.index, 1)
if @.CurrentChar NOT IN ('0', '1', '2', '3', '4', '5', '6', '7', '8', '9')
BEGIN
SET @.SearchString = REPLACE(@.SearchString, @.CurrentChar, 'X')
END
SET @.Index = @.Index + 1
END
SELECT REPLACE(@.SearchString, 'X','')
Returns 35021947
Replace all the non-numeric values with 'X' (so as to not screw up the WHILE
index,) then replace all Xs with an empty string. In a stored proc,
@.SearchString would be the parameter...
HTH,
Mike

Remove all non digit characters from some string

Hello.
How can I write some stored procedure or function to which I will pass the
string and it will return me only numbers from my string?
Exactly I need to remove all non digit characters from some string.
Tank you.You could write an extended stored proc in a dll...dont know if this best
solution though
"David Dvali" <david_dvali@.hotmail.com> wrote in message
news:%23iSW2D$0FHA.2348@.TK2MSFTNGP15.phx.gbl...
> Hello.
> How can I write some stored procedure or function to which I will pass the
> string and it will return me only numbers from my string?
> Exactly I need to remove all non digit characters from some string.
> Tank you.
>|||David,
If you have a fixed set of characters to remove i.e., like with a phone
number you could do something like this:
DECLARE @.TELEPHONENUMBER VARCHAR(25)
SET @.TELEPHONENUMBER = '(503)999-1851'
SELECT REPLACE(REPLACE(REPLACE(REPLACE(@.TELEPHO
NENUMBER,'(',''),')',''),'
',''),'-','')
HTH
Jerry
"David Dvali" <david_dvali@.hotmail.com> wrote in message
news:%23iSW2D$0FHA.2348@.TK2MSFTNGP15.phx.gbl...
> Hello.
> How can I write some stored procedure or function to which I will pass the
> string and it will return me only numbers from my string?
> Exactly I need to remove all non digit characters from some string.
> Tank you.
>|||Hi,
This might not be the most efficient way of doing it but it works :-)
DECLARE @.InputString varchar(32)
DECLARE @.OutputString varchar(32)
DECLARE @.i int
SET @.InputString =3D 'ABC123!=A3$456'
SET @.i =3D NULLIF(PATINDEX('%[0-9]%',@.InputString),0)
WHILE @.i IS NOT NULL
BEGIN
SET @.OutputString =3D isnull(@.OutputString,'') +
SUBSTRING(@.Inputstring, @.i, 1)
SET @.i =3D @.i +
NULLIF(PATINDEX('%[0- 9]%',SUBSTRING(@.InputString,@.i+1,len(@.In
putString))
),0)
END
SELECT @.OutputString -- This gives '123456'
I would normally use a auxilary numbers table instead of the loop, but
didn't have time to go through that in this example.
Jerry Spivey wrote:[vbcol=seagreen]
> David,
> If you have a fixed set of characters to remove i.e., like with a phone
> number you could do something like this:
> DECLARE @.TELEPHONENUMBER VARCHAR(25)
> SET @.TELEPHONENUMBER =3D '(503)999-1851'
> SELECT REPLACE(REPLACE(REPLACE(REPLACE(@.TELEPHO
NENUMBER,'(',''),')',''),'
> ',''),'-','')
> HTH
> Jerry
> "David Dvali" <david_dvali@.hotmail.com> wrote in message
> news:%23iSW2D$0FHA.2348@.TK2MSFTNGP15.phx.gbl...
the[vbcol=seagreen]|||This should do the trick...
DECLARE @.Index smallint
DECLARE @.SearchString varchar(25)
DECLARE @.StringLength smallint
DECLARE @.CurrentChar Char(1)
SET @.searchstring = 'ab35d0l2rle.p1C9,:$#47)('
SET @.StringLength = LEN(@.SearchString)
SET @.Index = 1
WHILE @.Index <= @.StringLength
BEGIN
SET @.CurrentChar = SUBSTRING(@.SearchString, @.index, 1)
if @.CurrentChar NOT IN ('0', '1', '2', '3', '4', '5', '6', '7', '8', '9')
BEGIN
SET @.SearchString = REPLACE(@.SearchString, @.CurrentChar, 'X')
END
SET @.Index = @.Index + 1
END
SELECT REPLACE(@.SearchString, 'X','')
Returns 35021947
Replace all the non-numeric values with 'X' (so as to not screw up the WHILE
index,) then replace all Xs with an empty string. In a stored proc,
@.SearchString would be the parameter...
HTH,
Mike